document.write( "Question 641527: Maria lights two candles of equal length at the same time. One candle takes 6 hours to burn out and the other takes 9. How much time will pass until the slower-burning candle is exactly twice as long as the faster-burning candle? \n" ); document.write( "
Algebra.Com's Answer #403727 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Maria lights two candles of equal length at the same time. \n" ); document.write( " One candle takes 6 hours to burn out and the other takes 9. \n" ); document.write( " How much time will pass until the slower-burning candle is exactly \n" ); document.write( " twice as long as the faster-burning candle? \n" ); document.write( ": \n" ); document.write( "It will be easier if we assign a length to the candle, 18\" is a good value \n" ); document.write( "then \n" ); document.write( "One candle burns 18/6 = 3\" per hr \n" ); document.write( "Other candle burns 18/9 = 2\" per hr \n" ); document.write( ": \n" ); document.write( "Let t = time for this to happen \n" ); document.write( "18 - 2t = 2(18 - 3t) \n" ); document.write( "18 - 2t = 36 - 6t \n" ); document.write( "-2t + 6t = 36 - 18 \n" ); document.write( "4t = 18 \n" ); document.write( "t = 18/4 \n" ); document.write( "t = 4 |