document.write( "Question 641380: Suppose you invested 10,000 dolllars, part at 6% annual interest and the rest on 9% annual interest. If you recieved 684 dollars in interest after one year, how much did you invest at each rate? Due tom. thanks! \n" ); document.write( "
Algebra.Com's Answer #403627 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint:\r
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\n" ); document.write( "\n" ); document.write( "x+y = 10000\r
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\n" ); document.write( "\n" ); document.write( "y = 10000-x\r
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\n" ); document.write( "\n" ); document.write( "0.06x + 0.09y = 684\r
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\n" ); document.write( "\n" ); document.write( "6x + 9y = 68400\r
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\n" ); document.write( "\n" ); document.write( "6x + 9(10000-x) = 68400\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x. Once you have your value of x, use it to find y.
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