document.write( "Question 641274: If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta.
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Algebra.Com's Answer #403596 by Alan3354(69443)\"\" \"About 
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If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta.
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\n" ); document.write( "csc = -5/3 --> sin = -3/5
\n" ); document.write( "b in the Q3
\n" ); document.write( "cos = -4/5
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\n" ); document.write( "sin(2b) = 2sin*cos = 24/25
\n" ); document.write( "cos(2b) = 7/25
\n" ); document.write( "tan(2b) = sin/cos = 24/7
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