document.write( "Question 641274: If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta.
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document.write( "Please help! I've been attempting this for over an hour and I can't get a correct answer! \n" );
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Algebra.Com's Answer #403596 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta. \n" ); document.write( "---------------------- \n" ); document.write( "csc = -5/3 --> sin = -3/5 \n" ); document.write( "b in the Q3 \n" ); document.write( "cos = -4/5 \n" ); document.write( "---- \n" ); document.write( "sin(2b) = 2sin*cos = 24/25 \n" ); document.write( "cos(2b) = 7/25 \n" ); document.write( "tan(2b) = sin/cos = 24/7 \n" ); document.write( " \n" ); document.write( " |