document.write( "Question 641211: Solve for x and show work;\r
\n" ); document.write( "\n" ); document.write( "(6x-7)/4 + (3x-5)/7 = (5x+78)/28
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Algebra.Com's Answer #403585 by JellyBeans(8)\"\" \"About 
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(6x-7)/4 + (3x-5)/7 = (5x+78)/28
\n" ); document.write( "Equate the equation to 0
\n" ); document.write( "(6x-7)/4 + (3x-5)/7 - (5x+78)/28 = 0
\n" ); document.write( "Get the LCD of the denominators 4,7 and 28
\n" ); document.write( "The LCD is 28
\n" ); document.write( "Divide the denominator of each term to the LCD\r
\n" ); document.write( "\n" ); document.write( "28 [(6x-7)/4 + (3x-5)/7 - (5x+78)/28 ] 28 = 0
\n" ); document.write( "7(6x-7) + 4 (3x-5) - 1(5x+78) = 0
\n" ); document.write( "42x - 49 + 12x - 20 - 5x - 78 = 0
\n" ); document.write( "Combine like terms
\n" ); document.write( "49x - 147 = 0
\n" ); document.write( "transpose -147 to get the value of x
\n" ); document.write( " 49x/49 = 147/49
\n" ); document.write( " x = 3
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