document.write( "Question 641195: 10x + 3y = 8
\n" ); document.write( " 2x + y = 2
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Algebra.Com's Answer #403582 by JellyBeans(8)\"\" \"About 
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10x + 3y = 8 will be Equation 1
\n" ); document.write( " 2x + y = 2 will be Equation 2\r
\n" ); document.write( "\n" ); document.write( "Equation (2) 2x+y=2
\n" ); document.write( " y=-2x+2\r
\n" ); document.write( "\n" ); document.write( "Substitute the expression into equation (1)\r
\n" ); document.write( "\n" ); document.write( " Equation (1): 10x+3(-2x+2)=8
\n" ); document.write( " 10x-6x+6=8
\n" ); document.write( " 4x+6=8
\n" ); document.write( " 4x=2
\n" ); document.write( " x=1/2\r
\n" ); document.write( "\n" ); document.write( "Substitute the answer to the expression obtained in equation (2)
\n" ); document.write( " y=-2x+2
\n" ); document.write( " y=-2(1/2)+2
\n" ); document.write( " y= 1\r
\n" ); document.write( "\n" ); document.write( "To check:
\n" ); document.write( " Eq (1): 10x + 3y = 8
\n" ); document.write( " 10(1/2)+3(1)=8
\n" ); document.write( " 5+3=8
\n" ); document.write( " 8=8\r
\n" ); document.write( "\n" ); document.write( " Eq (2): 2x + y = 2
\n" ); document.write( " 2(1/2)+1=2
\n" ); document.write( " 1+1=2
\n" ); document.write( " 2=2\r
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\n" ); document.write( "\n" ); document.write( "Btw, I'm 12 years old.
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