document.write( "Question 641198: Determine the bisector of the obtuse angle between the line 2x-3y=2 and x+y=6. Sketch the graph. \n" ); document.write( "
Algebra.Com's Answer #403576 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C600%2C+-10%2C+10%2C+-10%2C+10%2C+-x%2B6%2C+2x%2F3-2%2F3%29+\"\r
\n" ); document.write( "\n" ); document.write( "The slope of the bisecting line is NOT the average of the slopes of the two given lines.\r
\n" ); document.write( "\n" ); document.write( "We need to find a point on the line of intersection and its slope. First find the point of intersection of the lines:\r
\n" ); document.write( "\n" ); document.write( "\"2x+-+3y+=+2\"
\n" ); document.write( "\"x+%2B+y+=+6\"\r
\n" ); document.write( "\n" ); document.write( "The point of intersection is P(\"4\",\"+2\").\r
\n" ); document.write( "\n" ); document.write( "Find the slopes of the given lines.\r
\n" ); document.write( "\n" ); document.write( "\"m1+=+tan%28alpha%29+=+2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"m2+=+tan%28beta%29+=+-1\"\r
\n" ); document.write( "\n" ); document.write( "Note that for the first line \"alpha%3C+45\"°.
\n" ); document.write( "Note that for the second line \"beta+=+135\"°.\r
\n" ); document.write( "\n" ); document.write( "\"beta+-+alpha+%3E+90\"°\r
\n" ); document.write( "\n" ); document.write( "Therefore for the bisecting line of the obtuse angle:\r
\n" ); document.write( "\n" ); document.write( "\"m+=+tan%28%28alpha+%2B+beta%29%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "So the bisector of the obtuse angle will be \"near\"\"+vertical\".\r
\n" ); document.write( "\n" ); document.write( "The equation of the line will be:\r
\n" ); document.write( "\n" ); document.write( "\"y+-+2+=+m%28x+-4%29\"\r
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