document.write( "Question 641184: one number is 3 times another. the sum of their reciprocals is 20/3. find the numbers \n" ); document.write( "
Algebra.Com's Answer #403573 by josh_jordan(263)\"\" \"About 
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To solve, let's turn the sentences into equations. The first sentence says that one number is 3 times another. In other words:\r
\n" ); document.write( "\n" ); document.write( "x = 3y\r
\n" ); document.write( "\n" ); document.write( "The next sentence says that the sum of their reciprocals is 20/3. In other words:\r
\n" ); document.write( "\n" ); document.write( "\"1%2Fx+%2B+1%2Fy+=+20%2F3\"\r
\n" ); document.write( "\n" ); document.write( "To solve, we need to substitute x in the second equation, with 3y, that way we will get rid of x and solve for y:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F3y+%2B+1%2Fy+=+20%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Next, multiply the equation by 3y. This will get rid of our fractions and leave us with:\r
\n" ); document.write( "\n" ); document.write( "\"1+%2B+3+=+20y\" =\r
\n" ); document.write( "\n" ); document.write( "\"4+=+20y\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by 20, and this will leave us with y, which will be one of our numbers:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+4%2F20\" = \"y+=+1%2F5\"\r
\n" ); document.write( "\n" ); document.write( "So, 1/5 is one of our numbers. \r
\n" ); document.write( "\n" ); document.write( "We know that the other number is 3 times y. So, 3 x 1/5 will give us our other number:\r
\n" ); document.write( "\n" ); document.write( "3 x 1/5 = 3/5\r
\n" ); document.write( "\n" ); document.write( "FINAL ANSWER: 1/5 and 3/5 are the numbers
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