document.write( "Question 641114: A chemist has three acid solutions. The first contains 20% acid, the second contains 30% acid and the third contains 60% acid. She uses all three solutions to obtain a final mixture of 80 litres containing 40% acid. She uses twice as much of the 60% acid solution as the 20% solution. She wants to find out the number of litres of each solution she would use to obtain the final mixture.
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A chemist has three acid solutions. The first contains 20% acid, the second contains 30% acid and the third contains 60% acid. She uses all three solutions to obtain a final mixture of 80 litres containing 40% acid. She uses twice as much of the 60% acid solution as the 20% solution. She wants to find out the number of litres of each solution she would use to obtain the final mixture.
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\n" ); document.write( "let x=litres of 20% solution to be used
\n" ); document.write( "2x=litres of 60% solution to be used
\n" ); document.write( "(80-x-2x)=(80-3x) litres of 30% solution to be used
\n" ); document.write( "..
\n" ); document.write( "20%x+60%*2x+30%(80-3x)=40%*80
\n" ); document.write( ".2x+1.2x+24-.9x=32
\n" ); document.write( ".5x=32-24=8
\n" ); document.write( "x=16
\n" ); document.write( "2x=32
\n" ); document.write( "80-3x=32
\n" ); document.write( "..
\n" ); document.write( "litres of 20% solution to be used=16
\n" ); document.write( "litres of 60% solution to be used=32
\n" ); document.write( "litres of 30% solution to be used=32 \n" ); document.write( "

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