document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=640248>Question 640248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the ending balance in an account that opens with $3,590, earns 5.5% interest compounded monthly, and is held for 15 years. (round answer to nearestcent) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403532 by </B><A HREF=/tutors/aboutme.mpl?userid=cta1987><B>cta1987(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cta1987><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cta1987><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=P(1+r/n)^nt<BR>\n" );
document.write( "monthly=12 times per year<BR>\n" );
document.write( "rate=0.055<BR>\n" );
document.write( "P=3590<BR>\n" );
document.write( "t=15 years<BR>\n" );
document.write( "A=3590(1+0.055/12)^12*15<BR>\n" );
document.write( "A=3590(1+0.0458333333)^180<BR>\n" );
document.write( "A=3590(1.0458333333)^180<BR>\n" );
document.write( "A=3590(3186.0041424)<BR>\n" );
document.write( "A=11437754.79 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );