document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=641062>Question 641062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The time required to fill a tank varies inversely as the square of the diameter of the pipe used.  If it takes 20 hours to fill a given tank with a 2-in. pipe, find the diameter of the pipe needed to fill the same tank in 5 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403530 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Inverse variation means that t=k/d^2 where k is the constant of proportionality<BR>\n" );
document.write( "Sooo<BR>\n" );
document.write( "20 hrs=k/2^2 or<BR>\n" );
document.write( "k=80\r<BR>\n" );
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document.write( "Now<BR>\n" );
document.write( "5hrs=80/d^2<BR>\n" );
document.write( "5d^2=80<BR>\n" );
document.write( "d^2=16<BR>\n" );
document.write( "d=sqrt16=4 in\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "5hrs=80/4^2<BR>\n" );
document.write( "5hrs=80/16<BR>\n" );
document.write( "5hrs=5hrs\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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