document.write( "Question 640957: find an equation of the specified hyperbola with center at the origin.
\n" ); document.write( "with given Foci : ( +-10,0) ; Asymptotes: y=+-3/4x \n" ); document.write( "
Algebra.Com's Answer #403491 by lwsshak3(11628)\"\" \"About 
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find an equation of the specified hyperbola with center at the origin.
\n" ); document.write( "with given Foci : ( +-10,0) ; Asymptotes: y=+-3/4x
\n" ); document.write( "**
\n" ); document.write( "Give data shows this is a hyperbola with horizontal transverse axis.
\n" ); document.write( "Its standard form of equation: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center
\n" ); document.write( "Given center: (0,0)
\n" ); document.write( "Given slope of asymptotes=±3/4
\n" ); document.write( "For hyperbolas with horizontal transverse axis, slope of asymptotes=b/a=3/4
\n" ); document.write( "3a=4b
\n" ); document.write( "b=3a/4
\n" ); document.write( "Given Foci=±10
\n" ); document.write( "c=10
\n" ); document.write( "c^2=100=a^2+b^2=a^2+(3a/4)^2
\n" ); document.write( "a^2+9a^2/16=100
\n" ); document.write( "LCD:16
\n" ); document.write( "16a^2+9a^2=1600
\n" ); document.write( "25a^2=1600
\n" ); document.write( "a^2=1600/25=64
\n" ); document.write( "b^2=9a^2/16=9*64/16=36
\n" ); document.write( "Equation of given hyperbola:
\n" ); document.write( "\"x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1\"
\n" ); document.write( "\"x%5E2%2F64-y%5E2%2F36=1\"
\n" ); document.write( " \n" ); document.write( "
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