document.write( "Question 58832This question is from textbook
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document.write( ": 1. Fifteen accounting majors had an average grade of 90 on a finance exam. Seven marketing majors averaged 85, while ten finance majors averaged 93 on the same examine. What is the weighted mean for the 32 students taking the exam?\r
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document.write( "2. A distribution described as negatively skewed would have the following characteristics:
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document.write( "a. The mode between the median and mean, observing from left to right.
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document.write( "b. the mean between the median and mode, observing from left to right.
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document.write( "c. The median between the mean snd the mode, observing from left to right
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document.write( "d. The relative location of mean, median, and mode is impossible to determine without more information
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document.write( "e. None of the above\r
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document.write( "3. Which of the following measures of dispersion are based on deviations from the mean.
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document.write( "a. Variance
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document.write( "b. Standart deviation
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document.write( "c. All the above
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document.write( "d. None of the above\r
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document.write( "4. What is the relationship between the variance and the standart deviation?
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document.write( "a. Variance is the square root of the standard deviation
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document.write( "b. Variance is the square of the standard deviation
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document.write( "c. Variance is twice the the stardard deviation
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document.write( "d. No constant relationship between the variance and the standard deviation
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document.write( "
Algebra.Com's Answer #40346 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1. Fifteen accounting majors had an average grade of 90 on a finance exam. Seven marketing majors averaged 85, while ten finance majors averaged 93 on the same examine. What is the weighted mean for the 32 students taking the exam? \n" ); document.write( "(15*90+7*85+10*93)32=89.84 \n" ); document.write( "2. A distribution described as negatively skewed would have the following characteristics: \n" ); document.write( "a. The mode between the median and mean, observing from left to right. \n" ); document.write( "b. the mean between the median and mode, observing from left to right. \n" ); document.write( "c. The median between the mean snd the mode, observing from left to right \n" ); document.write( "d. The relative location of mean, median, and mode is impossible to determine without more information \n" ); document.write( "e. None of the above \n" ); document.write( "mean < mode ; so answer \"b\" \n" ); document.write( "-------------------- \n" ); document.write( "3. Which of the following measures of dispersion are based on deviations from the mean. \n" ); document.write( "a. Variance \n" ); document.write( "b. Standart deviation \n" ); document.write( "c. All the above \n" ); document.write( "d. None of the above \n" ); document.write( "Ans: \"c\" \n" ); document.write( "------------------ \n" ); document.write( "4. What is the relationship between the variance and the standart deviation? \n" ); document.write( "a. Variance is the square root of the standard deviation \n" ); document.write( "b. Variance is the square of the standard deviation \n" ); document.write( "c. Variance is twice the the stardard deviation \n" ); document.write( "d. No constant relationship between the variance and the standard deviation \n" ); document.write( "Ans: \"b\" \n" ); document.write( "-------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |