document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=640768>Question 640768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the quotient and remainder for (4x^3-5x^2+2x-6)/(x^2-3x). I know how to divide polynomials, but what is throwing me off is the (x^2-3x) part. Should I factor that out or can I just divide the first polynomial by that and solve? Do I need to instead divide by 0x^3+x^2-3x because the first polynomial has an exponent with a power of 3? It may just be easier if you would take me through it step by step instead. Thank you so much.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403427 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "I need to find the quotient and remainder for (4x^3-5x^2+2x-6)/(x^2-3x). I know how to divide polynomials, but what is throwing me off is the (x^2-3x) part. Should I factor that out or can I just divide the first polynomial by that and solve? Do I need to instead divide by 0x^3+x^2-3x because the first polynomial has an exponent with a power of 3? It may just be easier if you would take me through it step by step instead. Thank you so much. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You simply set this up as long-division of a polynomial, with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%5E3+-+5x%5E2+%2B+2x+-+6 ALIGN=MIDDLE  ALT=\"4x%5E3+-+5x%5E2+%2B+2x+-+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > as the dividend, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+3x ALIGN=MIDDLE  ALT=\"x%5E2+-+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > as the divisor. It's somewhat difficult to demonstrate it here.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I'll start you off though.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "When you do the 1st division, the 1st of the quotient-expression is 4x, which when multiplied by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+3x ALIGN=MIDDLE  ALT=\"x%5E2+-+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > gives you: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%5E3+-+12x%5E2 ALIGN=MIDDLE  ALT=\"4x%5E3+-+12x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );