document.write( "Question 640819: For how many positive two-digit integers is the ones digit greater than twice the tens digit? \n" ); document.write( "
Algebra.Com's Answer #403425 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "If the tens digit is 1, twice 1 is 2 and the digits that are greater than\r\n" ); document.write( "2 are 3,4,5,6,7,8,9. So that's 7 ways.\r\n" ); document.write( "\r\n" ); document.write( "If the tens digit is 2, twice 2 is 4 and the digits that are greater than\r\n" ); document.write( "4 are 5,6,7,8,9. So that's 5 ways.\r\n" ); document.write( "\r\n" ); document.write( "If the tens digit is 3, twice 3 is 6 and the digits that are greater than\r\n" ); document.write( "2 are 7,8,9. So that's 3 ways.\r\n" ); document.write( "\r\n" ); document.write( "If the tens digit is 4, twice 4 is 8 and the only digit greater than\r\n" ); document.write( "8 is 9. So that's 1 ways.\r\n" ); document.write( "\r\n" ); document.write( "The tens digit cannot be 5 or larger, since twice 5 is not a digit.\r\n" ); document.write( "\r\n" ); document.write( "So that 7+5+3+1 = 16 of them. Might as well list them all:\r\n" ); document.write( "\r\n" ); document.write( " 1. 13\r\n" ); document.write( " 2. 14\r\n" ); document.write( " 3. 15\r\n" ); document.write( " 4. 16\r\n" ); document.write( " 5. 17\r\n" ); document.write( " 6. 18\r\n" ); document.write( " 7. 19\r\n" ); document.write( " 8. 25\r\n" ); document.write( " 9. 26\r\n" ); document.write( "10. 27\r\n" ); document.write( "11. 28\r\n" ); document.write( "12. 29\r\n" ); document.write( "13. 37\r\n" ); document.write( "14. 38\r\n" ); document.write( "15. 39\r\n" ); document.write( "16. 49\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |