document.write( "Question 640801: If Y = 5 when x = 2, find Y, when x is 4\r
\n" ); document.write( "\n" ); document.write( "anyone know this I WOULD LOVE ANY HELP! :)
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Algebra.Com's Answer #403402 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "If \"y1+=+5\" when \"x1+=+2\", find \"y\", when \"x=4\" \r
\n" ); document.write( "\n" ); document.write( "\"only\" in case that \"y\" varies directly as \"x\"\r
\n" ); document.write( "\n" ); document.write( "we could also write this as a proportion:\r
\n" ); document.write( "\n" ); document.write( "\"x1%2Fy1=x%2Fy\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2F5+=+4%2Fy\"\r
\n" ); document.write( "\n" ); document.write( "\"2y+=+4%2A5\"\r
\n" ); document.write( "\n" ); document.write( "\"2y+=+20\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+10\"
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