document.write( "Question 640701: Mary Julie and Peter went to restaurant for dinner. Mary paid 1/3 of the total cost. Julie paid Half as much as Mary did and Peter paid the remaining $75. What was the total cost of dinner? \n" ); document.write( "
Algebra.Com's Answer #403370 by mananth(16946)\"\" \"About 
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let the cost of dinner be x\r
\n" ); document.write( "\n" ); document.write( "Mary paid x/3
\n" ); document.write( "Julie 1/2 * x/3= x/6\r
\n" ); document.write( "\n" ); document.write( "Balance $75 Peter paid\r
\n" ); document.write( "\n" ); document.write( "x/3 + x/6 +75 = x\r
\n" ); document.write( "\n" ); document.write( "x/3+x/6 -x= -75\r
\n" ); document.write( "\n" ); document.write( "LCD = 6\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 6
\n" ); document.write( "2x+x-6x=-450\r
\n" ); document.write( "\n" ); document.write( "-3x=-450
\n" ); document.write( "/-3
\n" ); document.write( "x=150\r
\n" ); document.write( "\n" ); document.write( "Mary paid 1/3 of 150 = $50
\n" ); document.write( "Julie paid 1/6 of 150 = $25
\n" ); document.write( "Peter paid $75\r
\n" ); document.write( "\n" ); document.write( "Add up
\n" ); document.write( "The total cost of dinner = $150
\n" ); document.write( "
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