document.write( "Question 640608: 2/3+3m/5=31/15 \n" ); document.write( "
Algebra.Com's Answer #403361 by jim_thompson5910(35256)\"\" \"About 
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\"2%2F3%2B3m%2F5=31%2F15\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"15%282%2Fcross%283%29%2B3m%2Fcross%285%29%29=15%2831%2Fcross%2815%29%29\" Multiply both sides by the LCD \"15\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"10%2B9m=31\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"9m=31-10\" Subtract \"10\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"9m=21\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"m=%2821%29%2F%289%29\" Divide both sides by \"9\" to isolate \"m\".\r
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\n" ); document.write( "\n" ); document.write( "\"m=7%2F3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"m=7%2F3\"
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