document.write( "Question 640630: So I am in AP calc this year, and I have to do a review test, and can't find any of my old trig stuff.. So I was wondering if I could get a refresher on how to: Find all solutions of the equation in the interval [0,2pi] A) 4cos(theta)=1+2cos(theta) \n" ); document.write( "

Algebra.Com's Answer #403360 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm going to use x in place of theta (it's easier to type)\r
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\n" ); document.write( "\n" ); document.write( "4cos(x)=1+2cos(x) \r
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\n" ); document.write( "\n" ); document.write( "4cos(x)-2cos(x) = 1\r
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\n" ); document.write( "\n" ); document.write( "2cos(x) = 1\r
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\n" ); document.write( "\n" ); document.write( "cos(x) = 1/2\r
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\n" ); document.write( "\n" ); document.write( "x = arccos(1/2)\r
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\n" ); document.write( "\n" ); document.write( "x = pi/3 or x = -pi/3\r
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\n" ); document.write( "\n" ); document.write( "x = pi/3 or x = -pi/3+2pi\r
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\n" ); document.write( "\n" ); document.write( "x = pi/3 or x = -pi/3+6pi/3\r
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\n" ); document.write( "\n" ); document.write( "x = pi/3 or x = 5pi/3 \n" ); document.write( "

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