document.write( "Question 640564: Give the following quadratic equation, find at the vertex, the axis of symmetry, the intercepts, the domain, the range, the interval where the function is increasing, the interval where the function is decreasing.
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document.write( " y=6x^2+10x+3 \n" );
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Algebra.Com's Answer #403343 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Give the following quadratic equation, find at the vertex, the axis of symmetry, the intercepts, the domain, the range, the interval where the function is increasing, the interval where the function is decreasing. \n" ); document.write( "y=6x^2+10x+3 \n" ); document.write( "complete the square \n" ); document.write( "y=6(x^2+5x/3+25/36)+3-25/6 \n" ); document.write( "y=6(x^2+5/6)^2+18/6-25/6 \n" ); document.write( "y=6(x^2+5/6)^2-7/6 \n" ); document.write( "This is an equation of a parabola that opens upwards \n" ); document.write( "Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex. \n" ); document.write( "vertex: (-5/6,-7/6) \n" ); document.write( "axis of symmetry: x=-5/6 \n" ); document.write( ".. \n" ); document.write( "y-intercept \n" ); document.write( "set x=0 \n" ); document.write( "y=0+0+3=3 \n" ); document.write( ".. \n" ); document.write( "x-intercepts \n" ); document.write( "set y=0 \n" ); document.write( "6x^2+10x+3=0 \n" ); document.write( "solve for x by quadratic formula: \n" ); document.write( "a=6, b=10, c=3 \n" ); document.write( "x≈-1.274 \n" ); document.write( "or \n" ); document.write( "x≈-.392 \n" ); document.write( ".. \n" ); document.write( "Range: [-7/6,∞) \n" ); document.write( "Domain: (-∞,∞) \n" ); document.write( ".. \n" ); document.write( "Interval function decreasing: (∞-5/6) \n" ); document.write( "Interval function increasing: (-5/6,∞)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |