document.write( "Question 640394: good day! please help me with this word problem. thank you!\r
\n" ); document.write( "\n" ); document.write( "The height of a painting is 16 inches greater than the width and the area of the painting is 720 square inches. Can it be hung in a 2 feet by 4 feet wall space?
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Algebra.Com's Answer #403173 by Earlsdon(6294)\"\" \"About 
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To answer this question, you'll need to find the height and width of the painting. Let h = the height and w = the width:
\n" ); document.write( "The area of the rectangular painting is expressed by:
\n" ); document.write( "\"A+=+h%2Aw\" but h = w+16 and A = 720, so making the appropriate substitutions, you get:
\n" ); document.write( "\"720+=+%28w%2B16%29%2Aw\" which, after some rearranging looks like:
\n" ); document.write( "\"w%5E2%2B16w-720+=+0\" Do you see how we get this? Now you can factor this quadratic:
\n" ); document.write( "\"%28w-20%29%28w%2B36%29+=+0\" which means that:
\n" ); document.write( "\"w+=+20\" or \"w+=+-36\" Discard the negative solution as the width must be a positive quantity.
\n" ); document.write( "So the width is 20 inches and the height is 36 (20+16) inches.
\n" ); document.write( "Convert to feet:
\n" ); document.write( "Width = 1ft 8in.
\n" ); document.write( "Height = 3 ft.
\n" ); document.write( "So you can see that the painting will fit in the allocated space.
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