document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=640393>Question 640393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose a chemist has 10% and 15% acid solutions in stock. how much of each should the chemist mix if 100ml of a 12% solution is desired? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403164 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First express the problem in terms of the amount of acid  in the acid solutions.<BR>\n" );
document.write( " For example, in 10ml of a 10% acid solution, there are 10% of 10ml (0.1(10)) of acid which gives us 1ml of acid.<BR>\n" );
document.write( "For this problem, if we lex x = the number of ml of 10% acid solution and (100-x) = the amount of 15% acid solution, we can express the amounts of acid thus:<BR>\n" );
document.write( "0.1x+0.15(100-x) = 0.12(100) Simplify and solve for x.<BR>\n" );
document.write( "0.1x+15-0.15x = 12<BR>\n" );
document.write( "-0.05x+15 = 12 Subtract 15<BR>\n" );
document.write( "-0.05x = -3 Divide by -0.05<BR>\n" );
document.write( "x = 60ml<BR>\n" );
document.write( "The chemist will need to mix 60ml of the 10% acid solution with (100-x = 40)ml of the 15% acid solution to obtain 100ml of 12% acid solution. </SPAN>\n" );
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