document.write( "Question 640211: John is about as old in days as Jake is in weeks.
\n" ); document.write( "John is also as many months as Jim is in years.
\n" ); document.write( "Together, the 3 of them are 140 years old.
\n" ); document.write( "How old is Jim?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #403160 by ankor@dixie-net.com(22740)\"\" \"About 
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John is about as old in days as Jake is in weeks.
\n" ); document.write( "John is also as many months as Jim is in years.
\n" ); document.write( "Together, the 3 of them are 140 years old.
\n" ); document.write( "How old is Jim?
\n" ); document.write( ":
\n" ); document.write( "Let the three guys be x, y, z respectively
\n" ); document.write( "x = john's age (all in yrs)
\n" ); document.write( "y = Jake's age
\n" ); document.write( "z = Jim's age
\n" ); document.write( ":
\n" ); document.write( "John is about as old in days as Jake is in weeks
\n" ); document.write( "365x = 52y
\n" ); document.write( "Divide both sides by 52
\n" ); document.write( "7x = y
\n" ); document.write( ":
\n" ); document.write( "John is also as many months as Jim is in years.
\n" ); document.write( "12x = z
\n" ); document.write( ":
\n" ); document.write( "Together, the 3 of them are 140 years old.
\n" ); document.write( "x + y + z = 140
\n" ); document.write( "replace y with 7x, replace z with 12x
\n" ); document.write( "x + 7x + 12x = 140
\n" ); document.write( "20x = 140
\n" ); document.write( "x = 140/20
\n" ); document.write( "x = 7 yrs old is John
\n" ); document.write( ":
\n" ); document.write( "Find Jim
\n" ); document.write( "z = 12(7)
\n" ); document.write( "z = 84 yrs old is Jim
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the sum of the 3 ages\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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