document.write( "Question 640276: Tina is going for a walk, traveling at 4 mph. After 30 minutes, David leaves on his bike to try to catch up; he is traveling at 13 mph. If he follows the same route, how long will it take him to catch up (in minutes)? How far will they both have traveled? \n" ); document.write( "
Algebra.Com's Answer #403142 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Tina's head start is \n" ); document.write( "Start a stopwatch when David leaves \n" ); document.write( "They will both travel for the same amount \n" ); document.write( "of time = \n" ); document.write( "Let \n" ); document.write( "---------------------------- \n" ); document.write( "Tina's equation: \n" ); document.write( "(1) \n" ); document.write( "David's equation: \n" ); document.write( "(2) \n" ); document.write( "------------- \n" ); document.write( "Substitute (2) into (1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "Convert to minutes and seconds \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "David catches up in 13 min 20 sec \n" ); document.write( "-------------------------- \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( "David travels 2.889 mi \n" ); document.write( "Tina also travels 2.889 mi in \n" ); document.write( "--------------------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "OK \n" ); document.write( " |