document.write( "Question 640276: Tina is going for a walk, traveling at 4 mph. After 30 minutes, David leaves on his bike to try to catch up; he is traveling at 13 mph. If he follows the same route, how long will it take him to catch up (in minutes)? How far will they both have traveled? \n" ); document.write( "
Algebra.Com's Answer #403142 by josmiceli(19441)\"\" \"About 
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Tina's head start is \"+4%2A.5+=+2+\" mi
\n" ); document.write( "Start a stopwatch when David leaves
\n" ); document.write( "They will both travel for the same amount
\n" ); document.write( "of time = \"t\" in hours
\n" ); document.write( "Let \"+d+\" = distance David travels in miles
\n" ); document.write( "----------------------------
\n" ); document.write( "Tina's equation:
\n" ); document.write( "(1) \"+d+-+2+=+4t+\"
\n" ); document.write( "David's equation:
\n" ); document.write( "(2) \"+d+=+13t+\"
\n" ); document.write( "-------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+13t+-+2+=+4t+\"
\n" ); document.write( "(1) \"+9t+=+2+\"
\n" ); document.write( "(1) \"+t+=+2%2F9+\"
\n" ); document.write( "Convert to minutes and seconds
\n" ); document.write( "\"+%282%2F9%29%2A60+=+40%2F3+\"
\n" ); document.write( "\"+40%2F3+=+13+%2B+1%2F3+\"
\n" ); document.write( "\"+%281%2F3%29%2A60+=+20+\"
\n" ); document.write( "David catches up in 13 min 20 sec
\n" ); document.write( "--------------------------
\n" ); document.write( "(2) \"+d+=+13%2A%282%2F9%29+\"
\n" ); document.write( "(2) \"+d+=+26%2F9+\"
\n" ); document.write( "(2) \"+d+=+2.889+\"
\n" ); document.write( "\"+d+-+2+=+.889+\"
\n" ); document.write( "David travels 2.889 mi
\n" ); document.write( "Tina also travels 2.889 mi in \"+30+%2B+13+\" min and \"+20+\" sec
\n" ); document.write( "---------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+2+=+4t+\"
\n" ); document.write( "(1) \"+26%2F9+-+2+=+4%2A%282%2F9%29+\"
\n" ); document.write( "(1) \"+26+-+18+=+8+\"
\n" ); document.write( "(1) \"+26+=+26+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );