document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=640297>Question 640297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 3 pm a plane leaves london to fly madrid, 1260km away. at 4 pm a plane leaves madrid to fly to london. the second plane flies 40km/h faster then the first. if the planes pass one another at 4:30 pm wat is the speed of each plane? i do not want an answer but i have no idea how to work it could you please help? </SPAN>\n" );
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document.write( "at 3 pm a plane leaves london to fly madrid, 1260km away. at 4 pm a plane leaves madrid to fly to london. the second plane flies 40km/h faster then the first. if the planes pass one another at 4:30 pm wat is the speed of each plane? i do not want an answer but i have no idea how to work it could you please help?\r<BR>\n" );
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document.write( "Let speed of slower plane = S<BR>\n" );
document.write( "Then speed of faster plane = S + 40\r<BR>\n" );
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document.write( "Time the slower plane takes to get to the “passing point” = 1.5 hours<BR>\n" );
document.write( "Time the faster plane takes to get to the “passing point” = ½ hour, or .5 hour\r<BR>\n" );
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document.write( "The planes will travel a total of 1,260 km<BR>\n" );
document.write( "Therefore, distance traveled by slower plane, plus distance traveled by faster plane, equals total distance. This gives us:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%281.5S+%2B+.5%28S+%2B+40%29+=+1260%29 ALIGN=MIDDLE  ALT=\"highlight_green%281.5S+%2B+.5%28S+%2B+40%29+=+1260%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solve for S and this will give you the slower plane’s speed. Add the slower plane’s speed to 40 and you have the faster plane’s speed.\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com  </SPAN>\n" );
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