document.write( "Question 640250: If sin x = 1/3 and sec y = 3/4, where x and y lie between 0 and pi/2, evaluate sin(x+y) \n" ); document.write( "
Algebra.Com's Answer #403079 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If sin x = 1/3 and sec y = 3/4, where x and y lie between 0 and pi/2, evaluate sin(x+y) \n" ); document.write( "------------ \n" ); document.write( "secant cannot be 3/4 (unless y is a complex number) \n" ); document.write( " |