document.write( "Question 640239: Ashley is driving to New York City. Suppose that the remaining distance to drive (in miles)is a linear function of her driving time (in minutes). When graphed, the function gives a line with a slope of -0.95.\r
\n" ); document.write( "\n" ); document.write( "Ashley has 58 miles remaining after 50 minutes of driving. How many miles were remaining after 38 minutes of driving?
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Algebra.Com's Answer #403077 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Plot time = \"t\" on the horizontal axis
\n" ); document.write( "Plot miles remaining = \"r\" on the vertical axis
\n" ); document.write( "The equation has the form \"+r+=+-.95t+%2B+r%5B0%5D+\"
\n" ); document.write( "where \"+r%5B0%5D+\" is the value of \"+r+\" at \"+t+=+0+\"
\n" ); document.write( "given:
\n" ); document.write( "\"+r+=+-.95t+%2B+r%5B0%5D+\"
\n" ); document.write( "\"+58+=+-.95%2A50+%2B+r%5B0%5D+\"
\n" ); document.write( "\"+58+=+-47.5+%2B+r%5B0%5D+\"
\n" ); document.write( "\"+r%5B0%5D+=+105.5+\"
\n" ); document.write( "So, the equation is:
\n" ); document.write( "\"+r+=+-.95t+%2B+105.5+\"
\n" ); document.write( "When \"+t+=+38+\"
\n" ); document.write( "\"+r+=+-.95%2A38+%2B+105.5+\"
\n" ); document.write( "\"+r+=+-36.1+%2B+105.5+\"
\n" ); document.write( "\"+r+=+69.4+\"
\n" ); document.write( "69.4 miles remained after 38 minutes of driving
\n" ); document.write( "Here's the plot:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-10%2C+100%2C+-20%2C+200%2C+-.95x+%2B+105.5+%29+\"
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