document.write( "Question 639080: Convert this general equation of a hyperbola to standard form.
\n" ); document.write( "-4x^2+y^2-8x-12y+36=0 \n" ); document.write( "
Algebra.Com's Answer #403054 by lwsshak3(11628)\"\" \"About 
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Convert this general equation of a hyperbola to standard form.
\n" ); document.write( "-4x^2+y^2-8x-12y+36=0
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\n" ); document.write( "-4x^2+y^2-8x-12y+36=0
\n" ); document.write( "-4x^2-8x+y^2-12y+36=0
\n" ); document.write( "complete the square
\n" ); document.write( "-4(x^2+2x+1)+(y^2-12y+36)=-36-4+36
\n" ); document.write( "-4(x+1)^2+(y-6)^2=-4
\n" ); document.write( "divide by -4
\n" ); document.write( "standard form of equation:\"%28x%2B1%29%5E2-%28y-6%29%5E2%2F4=1\"
\n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis (x-term leading)
\n" ); document.write( "Its standard generic form: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "center: (-1,6)
\n" ); document.write( "a^2=1
\n" ); document.write( "b^2=4\r
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