document.write( "Question 640041: A plane leaves New York for Los Angeles traveling at an average speed of 500 miles per hour. A second plane leaves from Los Angeles two hours later bound for New York, 3200 miles away. Taking advantage of the jetstream, the second plane averages 600 mph. How many hours after the first plane took off will the two planes pass each other? \n" ); document.write( "
Algebra.Com's Answer #403007 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A plane leaves New York for Los Angeles traveling at an average speed of 500 miles per hour. \n" ); document.write( " A second plane leaves from Los Angeles two hours later bound for New York, \n" ); document.write( " 3200 miles away. \n" ); document.write( " Taking advantage of the jetstream, the second plane averages 600 mph. \n" ); document.write( " How many hours after the first plane took off will the two planes pass each other? \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the 1st plane \n" ); document.write( "then \n" ); document.write( "(t-2) = travel time of the 2nd plane \n" ); document.write( ": \n" ); document.write( "When the two planes meet, they will have traveled a total of 3200 miles \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "500t + 600(t-2) = 3200 \n" ); document.write( "500t + 600t - 1200 = 3200 \n" ); document.write( "1100t = 3200 + 1200 \n" ); document.write( "1100t = 4400 \n" ); document.write( "t = 4400/1100 \n" ); document.write( "t = 4 hrs after the 1st plane takes off they will meet \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by finding the actual distance each plane traveled \n" ); document.write( "4(500) = 2000 \n" ); document.write( "2(600) = 1200 \n" ); document.write( "-------------- \n" ); document.write( "total d: 3200 \n" ); document.write( " \n" ); document.write( " |