document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58777>Question 58777</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073268620/algebrahomeworkh>Elementry and Intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> John can run his boat in the still water at a speed of 15 miles per hour. If he can go 12 miles downstream in the same time as it takes him to go 9 miles upstream, then what is the speed of the water currents?	  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40300 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12/(15+X)=9/(15-X)<BR>\n" );
document.write( "9(15+X)=12(15-X)<BR>\n" );
document.write( "135+9X=180-12X<BR>\n" );
document.write( "9X+12X=180-135<BR>\n" );
document.write( "21X=45<BR>\n" );
document.write( "X=45/21<BR>\n" );
document.write( "X=2.14 MPH IS THE SPEED OF THE WATER<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "12/(15+2.14)=9/(15-2.14)<BR>\n" );
document.write( "12/17.14=9/12.86<BR>\n" );
document.write( ".7=.7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );