document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1359>Question 1359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find y?<BR>\n" );
document.write( "The problem is: x-2y=0 (equation 1) 3x+y=0 (equation 2)<BR>\n" );
document.write( "Right now in my Algebra Honor class we're learning \"Solving Systems by Substituion\" and at first I understood it but now I can't seem to get the answer I want. I don't know what to do so please help!\r<BR>\n" );
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document.write( "Anna \"Haylea\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK, first we have to takes out both x and 3x from both equations, so lets multiply equation 1 by -3 so then we can takes the x-terms away from both equations:<BR>\n" );
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document.write( "(equation 1)<BR>\n" );
document.write( "(-3)(x-2y) = 0(-3)<BR>\n" );
document.write( "-3x+6y = 0<BR>\n" );
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document.write( "So now we can use substituion now<BR>\n" );
document.write( "-3x+6y = 0<BR>\n" );
document.write( "3x+y = 0<BR>\n" );
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document.write( "7y = 0<BR>\n" );
document.write( "y = 0<BR>\n" );
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document.write( "So y is equal to zero </SPAN>\n" );
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