document.write( "Question 639932: (x-3)(x-2)=14 \n" ); document.write( "
Algebra.Com's Answer #402933 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
To solve, first expand the left side of the equal sign:\r
\n" ); document.write( "\n" ); document.write( "(x - 3)(x - 2) = \"x%5E2+-+5x+%2B+6+=+14\"\r
\n" ); document.write( "\n" ); document.write( "Next, subtract 14 from both sides of the equation:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+5x+%2B+6+-+14+=+14+-+14\"\r
\n" ); document.write( "\n" ); document.write( "This gives us\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+5x+-+8+=+0\"\r
\n" ); document.write( "\n" ); document.write( "We unfortunately cannot factor this quadratic equation, so from this point, we could try completing the square or using the quadratic formula. Let's use the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-5%29%2B-sqrt%28-5%5E2-4%2A1%2A%28-8%29%29%29%2F%282%2A1%29\", which reduces down to\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%285%2B-sqrt%2825%2B32%29%29%2F2\" = \"x+=+5%2B-sqrt%2857%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "FINAL ANSWER: \"x+=+%285%2Bsqrt%2857%29%29%2F2\" AND \"x+=+%285-sqrt%2857%29%29%2F2\"\r
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