document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=639879>Question 639879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3y+5(y-3)/2=3-y+2/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402908 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3y+5(y-3)/2=3-y+2/3<BR>\n" );
document.write( "multiplying 6 on both sides<BR>\n" );
document.write( "18y+15y-45=18-6y+4<BR>\n" );
document.write( "or 39y=22+45=67<BR>\n" );
document.write( "or y=67/39 ans </SPAN>\n" );
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