document.write( "Question 639824: Jo invested part of her $8000 at 12% and part at 8%. If the annual investment income is $825, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #402882 by mananth(16946) $\"\"$ $\"About$

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Investment I 12.00% per annum ------------- Amount invested =x
\n" ); document.write( "Investment II 8.00% per annum ------------ Amount invested = y
\n" ); document.write( " 8000
\n" ); document.write( "Interest----- 825
\n" ); document.write( "
\n" ); document.write( "Investment I 12.00% per annum ---x
\n" ); document.write( "Investment II 8.00% per annum ---y
\n" ); document.write( "Credit on both cards
\n" ); document.write( "x + 1 y= 8000 -------------1
\n" ); document.write( "Interestto be paid on both
\n" ); document.write( "12.00% x + 8.00% y= 825
\n" ); document.write( "Multiply by 100
\n" ); document.write( "12 x + 8 y= 82500.00 --------2
\n" ); document.write( "Multiply (1) by -12
\n" ); document.write( "we get
\n" ); document.write( "-12 x -12 y= -96000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -4 y= -13500
\n" ); document.write( "divide by -4
\n" ); document.write( " y = 3375
\n" ); document.write( "Investment I 12.00% $ 4625
\n" ); document.write( "Investment II 8.00% $ 3375
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "4625 --------- 12.00% ------- 555.00
\n" ); document.write( "3375 ------------- 8.00% ------- 270.00
\n" ); document.write( "Total -------------------- 825.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
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