document.write( "Question 639817: Simplify: sinx(cotx+cscx).
\n" ); document.write( "I know that the answer is supposed to come out to be cosx+1 but, I am unsure on how to get there. I know that certain functions can be switched but this is for a review from a previous class so I don't remember exactly how to do it. If you are willing to help it would be much appreciated. Thanks
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Algebra.Com's Answer #402876 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\"sinx%28cotx%2Bcscx%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sinx%28%28cosx%2Fsinx%29+%2B+%281%2Fsinx%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sinx%28Cosx%2B1%29%2Fsinx%29\"\r
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\n" ); document.write( "\n" ); document.write( "= Cosx+1\r
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