document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=639601>Question 639601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use substitution to solve for x1 and y1<BR>\n" );
document.write( "y=x2<BR>\n" );
document.write( "y=6x-5<BR>\n" );
document.write( "i already figured out that x2=5 and y2=25. and yes i am sure those are correct </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402825 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have y = x^2 and you have y = 6x - 5<BR>\n" );
document.write( "since they are both equal to y, then they are both equal to each other and you get x^2 = 6x - 5<BR>\n" );
document.write( "subtract 6x and add 5 to both sides of this equation to get x^2 - 6x + 5 = 0<BR>\n" );
document.write( "this a quadratic equation whose factors are (x-5) * (x-1)<BR>\n" );
document.write( "your equation becomes (x-5) * (x-1) = 0<BR>\n" );
document.write( "since each of these factors can be set equal to 0, you get:<BR>\n" );
document.write( "x-5 = 0 and x-1 = 0<BR>\n" );
document.write( "solve for x in both these equations to get x = 5 and x = 1<BR>\n" );
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