document.write( "Question 58738: A six-passenger plane cruises at 180 mph in calm air. If the plane flies 7 miles with the wind in the same amount of time as it flies 5 miles against the wind, then what is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #40281 by checkley71(8403) ![]() You can put this solution on YOUR website! 180/(x+5)=5 \n" ); document.write( "180/(x-5)=7 \n" ); document.write( "180/(x+5)+2=180/(x-5) \n" ); document.write( "(180+2X+10)/(x+5)=180/(X-5) \n" ); document.write( "(190+2X)/(X+5)=180/(X-5) \n" ); document.write( "180(X+5)=(190+2X)(X-5) \n" ); document.write( "180X+900=190X+2X^2-950-10X \n" ); document.write( "2X^2+190X-10X-180X-950-900=0 \n" ); document.write( "2X^2-1850=0 \n" ); document.write( "X^2-925=0 \n" ); document.write( "(X-30.41)(X+30.41)=0 \n" ); document.write( "X-30.41=0 \n" ); document.write( "X=30.41 MPH FOR THE WIND. \n" ); document.write( "PROOF \n" ); document.write( "180/(30.42+5)=5 \n" ); document.write( "180/35.41=5 \n" ); document.write( "5=5 \n" ); document.write( "180/(30.41-5)=7 \n" ); document.write( "180/25.41=7 \n" ); document.write( "7=7\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |