document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58759>Question 58759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir,Madam,\r<BR>\n" );
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document.write( "Please can you help me to solve following?\r<BR>\n" );
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document.write( "The number of passengers on the Carnival Sensation during one-week cruises in the Caribbean follows the normal distribution. The mean number of passengers per cruise is 1,820 and the standard deviation is 120.<BR>\n" );
document.write( "a) what percent of the cruises will have between1,820 and 1,970 passengers?<BR>\n" );
document.write( "b) what percent of the cruises will have 1,970 passengers or more?<BR>\n" );
document.write( "c) what percent of the cruises will have 1,600 or fewer passengers?<BR>\n" );
document.write( "d) how many passengers are on the cruises with the fewet 25 percent of passengers?\r<BR>\n" );
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document.write( "I would really appreciate your help as this is the only exercise I have been unable to answer.\r<BR>\n" );
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document.write( "Thanks very much,\r<BR>\n" );
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document.write( "Gerald Bremer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40280 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of passengers on the Carnival Sensation during one-week cruises in the Caribbean follows the normal distribution. The mean number of passengers per cruise is 1,820 and the standard deviation is 120.<BR>\n" );
document.write( "a) what percent of the cruises will have between1,820 and 1,970 passengers?<BR>\n" );
document.write( "P(1820<=X<=1970)=P((1820-1820))/120<=z<=(1970-1820))/120))=0.394\r<BR>\n" );
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document.write( "b) what percent of the cruises will have 1,970 passengers or more?<BR>\n" );
document.write( "P(X>=1970)=P(z>=(1970-1820)/120)=0.1056\r<BR>\n" );
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document.write( "c) what percent of the cruises will have 1,600 or fewer passengers?<BR>\n" );
document.write( "P(x<=1600)=P(z<=(1600-1820)/120))=0.0334<BR>\n" );
document.write( "d) how many passengers are on the cruises with the fewet 25 percent of passengers? <BR>\n" );
document.write( "Find the z-value that corresponds to the bottom 25% of population:<BR>\n" );
document.write( "z=-0.6745<BR>\n" );
document.write( "Then solve for X in:<BR>\n" );
document.write( "-0.6745=(X-1820)/120<BR>\n" );
document.write( "X-1820= -80.94<BR>\n" );
document.write( "X<=1719 passengers are on the cruise.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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