document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=639535>Question 639535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The  length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 414 feet, find the width and the length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402788 by </B><A HREF=/tutors/aboutme.mpl?userid=kainharen><B>kainharen(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kainharen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of rectangle = 2(l+b)<BR>\n" );
document.write( "so according to question  length of  rectangle is 3 feet less than twice the width of the rectangle<BR>\n" );
document.write( "so<BR>\n" );
document.write( "let the width of rectangle=x<BR>\n" );
document.write( "then the length of rectangle= 2x-3\r<BR>\n" );
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document.write( "2[(2x-3)+x]=414 <BR>\n" );
document.write( "4x-6+2x=414<BR>\n" );
document.write( "6x=414+6<BR>\n" );
document.write( "x=420/6 \r<BR>\n" );
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document.write( "x=70 \r<BR>\n" );
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document.write( "then,\r<BR>\n" );
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document.write( "length of rectangle= 2x-3=140-3=137 feets. \r<BR>\n" );
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document.write( "Widt of rectangle= 70 feets.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );