document.write( "Question 639474: Two investments totaling $16,000 produce an annual income of $1140. One investment yields at 6% a year, while the other yields at 8% per year. How much is invested at each rate?
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document.write( "I have read this word problem over 20 times. Please help solve this word problem.\r
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document.write( "principal=16,000
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document.write( "interest=1140
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document.write( "rate \n" );
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Algebra.Com's Answer #402783 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Two investments totaling $16,000 produce an annual income of $1140. One investment yields at 6% a year, while the other yields at 8% per year. How much is invested at each rate? \n" ); document.write( "I have read this word problem over 20 times. Please help solve this word problem.\r \n" ); document.write( "\n" ); document.write( "principal=16,000 \n" ); document.write( "interest=1140 \n" ); document.write( "rate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let amount invested at 6% be S \n" ); document.write( "Then amount invested at 8% = 16,000 - S\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Interest earned at 6%, plus interest earned at 8%, equals total interest earned \n" ); document.write( "We therefore have: .06(S) + .08(16,000 - S) = 1,140\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".06S + 1,280 - .08S = 1,140\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".06S - .08S = 1,140 - 1,280\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "- .02S = - 140\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S, or amount invested at 6% = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Amount invested at 8% = $16,000 - 7,000, or $ \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |