document.write( "Question 639485: Here is the problem:\r
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document.write( "If a≠b and 1/x + 1/a = 1/b , then x= \r
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document.write( "I just can't seem to isolate x. The closest I got was 1/x= b-a/ab.\r
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document.write( "Could you please guide me to the isolation of x?\r
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document.write( "Thank you!\r
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Algebra.Com's Answer #402778 by MathTherapy(10555)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is the problem:\r \n" ); document.write( "\n" ); document.write( "If a≠b and 1/x + 1/a = 1/b , then x= \r \n" ); document.write( "\n" ); document.write( "I just can't seem to isolate x. The closest I got was 1/x= b-a/ab.\r \n" ); document.write( "\n" ); document.write( "Could you please guide me to the isolation of x?\r \n" ); document.write( "\n" ); document.write( "Thank you!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ab + bx = ax ------- Multiplying by LCD, abx to clear fractions\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "bx - ax = - ab\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(b - a) = - ab\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |