document.write( "Question 639514: 4a + 9b = 8
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document.write( "8a + 6c = -1
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document.write( "6b + 6c = -1 \n" );
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Algebra.Com's Answer #402773 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! 4a + 9b = 8 \n" ); document.write( "8a + 6c = -1 \n" ); document.write( "6b + 6c = -1 \n" ); document.write( " \r\n" ); document.write( "Write the system so that the terms of like variables\r\n" ); document.write( "line up vertically like this\r\n" ); document.write( "\r\n" ); document.write( "4a + 9b = 8\r\n" ); document.write( "8a + 6c = -1\r\n" ); document.write( " 6b + 6c = -1\r\n" ); document.write( "\r\n" ); document.write( "The letter c does not appear in the first equation, thus \r\n" ); document.write( "c is already eliminated from the first equation\r\n" ); document.write( "\r\n" ); document.write( "So we will eliminate c from the other two equations.\r\n" ); document.write( "\r\n" ); document.write( "We multiply the 3rd equation by -1 and add it to the\r\n" ); document.write( "2nd equation \r\n" ); document.write( "\r\n" ); document.write( "8a + 6c = -1\r\n" ); document.write( " -6b - 6c = 1\r\n" ); document.write( "-----------------\r\n" ); document.write( "8a - 6b = 0\r\n" ); document.write( "\r\n" ); document.write( "That can be divided through by 2\r\n" ); document.write( "\r\n" ); document.write( "4a - 3b = 0\r\n" ); document.write( "\r\n" ); document.write( "Now we have a system of 2 equations in 2 unknowns a and b\r\n" ); document.write( "\r\n" ); document.write( "4a + 9b = 8\r\n" ); document.write( "4a - 3b = 0\r\n" ); document.write( "\r\n" ); document.write( "Multiplying the bottom equation by -1 and adding to the first\r\n" ); document.write( "equation:\r\n" ); document.write( "\r\n" ); document.write( " 4a + 9b = 8\r\n" ); document.write( "-4a + 3b = 0\r\n" ); document.write( "------------\r\n" ); document.write( " 12b = 8\r\n" ); document.write( " b = \n" ); document.write( " \n" ); document.write( " |