document.write( "Question 639495: I need help solving this equation and checking the solution.\r
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document.write( "9x+1=8x+4\r
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document.write( "Do I add 9x and 8x together then 1 and 4, not sure? \n" );
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Algebra.Com's Answer #402766 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I need help solving this equation and checking the solution.\r \n" ); document.write( "\n" ); document.write( "9x+1=8x+4\r \n" ); document.write( "\n" ); document.write( "Do I add 9x and 8x together then 1 and 4, not sure?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x + 1 = 8x + 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the variables are on different sides, we need to get both on the same side. We can therefore choose to get rid of the variable on the right-side by subtracting 8x. When 8x is subtracted from the left side, it leaves 0 + 4 on the right side, and the left-side becomes 9x - 8x + 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Likewise, you subtract 1 from the left-side in order to get rid of the 1. Now we have: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x - 8x + 1 - 1 = 8x - 8x + 4 - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can now substitute 3 for x in the original equation to determine if that solution makes the equation true, and it does, as seen below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9(3) + 1 = 8(3) + 4 \n" ); document.write( "27 + 1 = 24 + 4 \n" ); document.write( "28 = 28 (TRUE)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |