document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=639398>Question 639398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't even know where to begin with this, please help explain the steps.\r<BR>\n" );
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document.write( "Solve: 2*log4(x)+3*log8(x)=10\r<BR>\n" );
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document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402719 by </B><A HREF=/tutors/aboutme.mpl?userid=opeodu><B>opeodu(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=opeodu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=opeodu><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2Log4x+3log8x=10 log4x^2+log8x^3=10 using law of logarithm that log(baseN^b)a=1/blog(baseN)a 1/2log2x^2+1/3log2x^3 log2x+log2x=10 log2x^2=10 x^2=2^10 x=2^5=32 </SPAN>\n" );
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