document.write( "Question 639304: How do I factor 25y^2 - 10y + 1? \r
\n" ); document.write( "\n" ); document.write( "I thought it was a perfect square trinomial, but that doesn't make sense because of the + 1. And I tried factoring it out by taking 5y out, but that doesn't match the answer in the back of my book. I don't know how they got that answer. The answer to the question is (5y - 1)^2.
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Algebra.Com's Answer #402714 by MathTherapy(10555)\"\" \"About 
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\n" ); document.write( "How do I factor 25y^2 - 10y + 1? \r
\n" ); document.write( "\n" ); document.write( "I thought it was a perfect square trinomial, but that doesn't make sense because of the + 1. And I tried factoring it out by taking 5y out, but that doesn't match the answer in the back of my book. I don't know how they got that answer. The answer to the question is (5y - 1)^2.\r
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\n" ); document.write( "\n" ); document.write( "\"25y%5E2+-+10y+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "We're looking for 2 factors whose product is + 25 (c * a), and whose sum is - 10 (b). These 2 factors are: - 5 and - 5, thus making the replacement for - 10y, - 5y and - 5y.\r
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\n" ); document.write( "\n" ); document.write( "We now have: \"25y%5E2+-+5y+-+5y+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2825y%5E2++-+5y%29+-+%285y+%2B+1%29\"\r
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\n" ); document.write( "\n" ); document.write( "5y(5y - 1) - 1(5y - 1)\r
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\n" ); document.write( "\n" ); document.write( "(5y - 1)(5y - 1), or \"highlight_green%28%285y+-+1%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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