document.write( "Question 639379: A square garden has an area of 841 squared feet, and the gardener wants to install a sprinkler (with a circluar spraying pattern) at the center of the garden. What is the minimum radius of spray the sprinkler would need in order to water all of the garden?
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Algebra.Com's Answer #402708 by mananth(16946) $\"\"$ $\"About$

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The sprinkling radius will have to be half the length of the diagonal of the square garden.\r
\n" ); document.write( "\n" ); document.write( "Garden is a square
\n" ); document.write( "The diagonal and the sides of square form a right triangle.
\n" ); document.write( "so the diagonal is the hypotenuse with the sides as the other two sides of a right triangle\r
\n" ); document.write( "\n" ); document.write( "let the length of side of square be x\r
\n" ); document.write( "\n" ); document.write( "area = x*x = x^2
\n" ); document.write( "x^2= 841
\n" ); document.write( "x= sqrt(841) = 29
\n" ); document.write( "side = 29\r
\n" ); document.write( "\n" ); document.write( "Apply pythagoras theorem
\n" ); document.write( "diagonal ^2= 29^2+29^2
\n" ); document.write( "diagonal^2= 1682
\n" ); document.write( "diagonal = 41.01 \r
\n" ); document.write( "\n" ); document.write( "half the diagonal = 20.5 feet\r
\n" ); document.write( "\n" ); document.write( "The radius of the sprinkler \n" ); document.write( "

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