document.write( "Question 58728This question is from textbook Elementary and Intermediate Algebra
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document.write( ": The width of a rectangle is 3 inches less than one-half of its length. If the perimeter of the rectangle is 42 inches, find the area of the rectangle. \n" );
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Algebra.Com's Answer #40270 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2*LENGTH*2WIDTH=42 \n" ); document.write( "LENGTH=X \n" ); document.write( "WIDTH=(X/2)-3 \n" ); document.write( "THEN \n" ); document.write( "2X+2(X/2-3)=42 \n" ); document.write( "2X+2X/2-6=42 \n" ); document.write( "(4X+2X)/2=42+6 \n" ); document.write( "6X/2=48 \n" ); document.write( "6X=96 \n" ); document.write( "X=16 WHICH IS THE LENGTH \n" ); document.write( "THEN WIDTH=16/2-3 \n" ); document.write( "OR WIDTH=8-3=5 \n" ); document.write( "PROOF \n" ); document.write( "2*16+2*5=42 \n" ); document.write( "32+10=42 \n" ); document.write( "42=42 \n" ); document.write( " \n" ); document.write( " |