document.write( "Question 58728This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": The width of a rectangle is 3 inches less than one-half of its length. If the perimeter of the rectangle is 42 inches, find the area of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #40270 by checkley71(8403)\"\" \"About 
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2*LENGTH*2WIDTH=42
\n" ); document.write( "LENGTH=X
\n" ); document.write( "WIDTH=(X/2)-3
\n" ); document.write( "THEN
\n" ); document.write( "2X+2(X/2-3)=42
\n" ); document.write( "2X+2X/2-6=42
\n" ); document.write( "(4X+2X)/2=42+6
\n" ); document.write( "6X/2=48
\n" ); document.write( "6X=96
\n" ); document.write( "X=16 WHICH IS THE LENGTH
\n" ); document.write( "THEN WIDTH=16/2-3
\n" ); document.write( "OR WIDTH=8-3=5
\n" ); document.write( "PROOF
\n" ); document.write( "2*16+2*5=42
\n" ); document.write( "32+10=42
\n" ); document.write( "42=42
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