document.write( "Question 58739: I need help on multipying and taking \"i\" to powers.\r
\n" );
document.write( "\n" );
document.write( "My question is:\r
\n" );
document.write( "\n" );
document.write( "Evaluate the following epression for x=2i\r
\n" );
document.write( "\n" );
document.write( "x^6 + 3x^3 - 4x^2 + 2x - 5\r
\n" );
document.write( "\n" );
document.write( "I used the dividing power rule on one of the worked problems. The answer I got was -7 from this equation:\r
\n" );
document.write( "\n" );
document.write( "2(-1) + 3(2)(-i) - 4(2)(-1) + 2(i) - 5\r
\n" );
document.write( "\n" );
document.write( "-2 + 6(-i) + 8 + 2i - 5\r
\n" );
document.write( "\n" );
document.write( "1 + 8
\n" );
document.write( "1 + 8(-1)(1)
\n" );
document.write( "1 - 8 \n" );
document.write( "
Algebra.Com's Answer #40269 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! I need help on multipying and taking \"i\" to powers. \n" ); document.write( "i^0=1 \n" ); document.write( "i^1=i \n" ); document.write( "i^2=-1 \n" ); document.write( "i^3=-i \n" ); document.write( "Whenever the powers are bigger than 3, divide the power by 4, whatever the remainder is tells you what you have: \n" ); document.write( "i^4=1 ( because 4/4=1 r=0 and i^0=1) \n" ); document.write( "i^13=i (because 13/4=3 r=1 and i^1=i) \n" ); document.write( "i^102=-1 (because 102/4=25 r=2 and i^2=-1) \n" ); document.write( ": \n" ); document.write( "Evaluate the following epression for x=2i \n" ); document.write( ": \n" ); document.write( "x^6 + 3x^3 - 4x^2 + 2x - 5 \n" ); document.write( "(2i)^6+3(2i)^3-4(2i)^2+2(2i)-5 \n" ); document.write( "64(-1)+3(8)(-i)-4(4)(-1)+4i-5 \n" ); document.write( "-64-24i+16+4i-5 \n" ); document.write( "-53-20i \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |