document.write( "Question 58708: 4y + square root 3 x = 8\r
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document.write( " 3y + 4x = -6 \r
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document.write( " Is there a solution - how do I graph this system? Please help.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #40259 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st: 4y + square root 3 x = 8 \n" ); document.write( "2nd: 3y + 4x = -6 \n" ); document.write( "--------------- \n" ); document.write( "Multiply 1st by 3 and 2nd by 4 to get: \n" ); document.write( "3rd: 12y+3sqrt3 x = 24 \n" ); document.write( "4th: 12y+16x = -24 \n" ); document.write( "--------------- \n" ); document.write( "Subtract 4th from 3rd to get: \n" ); document.write( "5th: (3sqrt3 -16)x=48 \n" ); document.write( "x=48/(3sqrt3 - 16) \n" ); document.write( "x=-4.44286... \n" ); document.write( "--------------- \n" ); document.write( "Substitute in 2nd to solve for y, as follows: \n" ); document.write( "3y +4(-4.442861643)=-6 \n" ); document.write( "3y - 17.7714467...=-6 \n" ); document.write( "3y=11.77144657... \n" ); document.write( "y=3.923815524... \n" ); document.write( "------------ \n" ); document.write( "These value check in 3rd \n" ); document.write( "------------------------ \n" ); document.write( "You should be able to graph the original equations as: \n" ); document.write( "y=(1/4)(8-(sqrt3)x) \n" ); document.write( "y=(1/3)(-6-4x) \n" ); document.write( " \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |