document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=639038>Question 639038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 70% methyl solution should be added to 200 liters of a 20% methyl solution to obtain a 35% methyl solution?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402533 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 70% methyl solution needed<BR>\n" );
document.write( "Now we know that the amount of pure methyl that exists before the mixture takes place(0.70x+0.20*200) has to equal the amount of pure methyl that exists after the mixture takes place (0.35(200+x)).  Sooooo:<BR>\n" );
document.write( "0.70x+0.20*200=0.35(200+x) simplify<BR>\n" );
document.write( "0.70x+40=70+0.35x  subtract 40 and also 0.35x from each side<BR>\n" );
document.write( "0.70x-0.35x=70-40 collect like terms<BR>\n" );
document.write( "0.35x=30<BR>\n" );
document.write( "x=85.7 liters amount of 70% methyl needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "0.70*85.7+0.20*200=0.35*285.7<BR>\n" );
document.write( "59.99+40=99.995<BR>\n" );
document.write( "99.99~~~~99.995\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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