document.write( "Question 638925: The perimeter of a rectangle is 170 feet. If the length exceeds 5 times the width by 1 foot,then what is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #402496 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The perimeter of a rectangle is 170 feet. If the length exceeds 5 times the width by 1 foot,then what is the area of the rectangle?\r
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\n" ); document.write( "\n" ); document.write( "Let width be W
\n" ); document.write( "Then length = 5W + 1\r
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\n" ); document.write( "\n" ); document.write( "Since 2L + 2W = P, we now have: 2(5W + 1) + 2W = 170\r
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\n" ); document.write( "\n" ); document.write( "10W + 2 + 2W = 170\r
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\n" ); document.write( "\n" ); document.write( "12W = 168\r
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\n" ); document.write( "\n" ); document.write( "W, or width = \"168%2F12\", or 14 ft\r
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\n" ); document.write( "\n" ); document.write( "Length = 5(14) + 1, or 71 feet ------ Substituting 14 for W\r
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\n" ); document.write( "\n" ); document.write( "Area = 14(71), or \"highlight_green%28994%29\" sq ft\r
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